Regarding the RL parallel circuit, this article will explain the information below.

- Equation, magnitude, vector diagram, and admittance phase angle of RL parallel circuit admittance

## Admittance of the RL parallel circuit

An RL parallel circuit is an electrical circuit consisting of a resistor \(R\) and an inductor \(L\) connected in parallel, driven by a voltage source or current source.

The impedance \({\dot{Z}}_R\) of the resistor \(R\) and the impedance \({\dot{Z}}_L\) of the inductor \(L\) can be expressed by the following equations:

\begin{eqnarray}

{\dot{Z}_R}&=&R\tag{1}\\

\\

{\dot{Z}_L}&=&jX_L=j{\omega}L\tag{2}

\end{eqnarray}

, where \({\omega}\) is the angular frequency, which is equal to \(2{\pi}f\), and \(X_L\left(={\omega}L\right)\) is called inductive reactance, which is the resistive component of inductor \(L\).

Since admittance is the reciprocal of impedance, the admittance \({\dot{Y}}_R\) of resistor \(R\) and the admittance \({\dot{Y}}_L\) of inductor \(L\) can each be expressed by the following equations.

\begin{eqnarray}

{\dot{Y}_R}&=&\frac{1}{{\dot{Z}_R}}=\frac{1}{R}\tag{3}\\

\\

{\dot{Y}_L}&=&\frac{1}{{\dot{Z}_L}}=\frac{1}{j{\omega}L}=-j\frac{1}{{\omega}L}\tag{4}

\end{eqnarray}

The admittance \({\dot{Y}}\) of the RL parallel circuit is the sum of the respective admittances, and is as follows:

\begin{eqnarray}

{\dot{Y}}&=&{\dot{Y}_R}+{\dot{Y}_L}\\

\\

&=&\frac{1}{R}+\frac{1}{j{\omega}L}\\

\\

&=&\frac{1}{R}-j\frac{1}{{\omega}L}\tag{5}

\end{eqnarray}

From the above, the admittance \({\dot{Y}}\) of the RL parallel circuit becomes the following equation.

Admittance of the RL parallel circuit

\begin{eqnarray}

{\dot{Y}}=\frac{1}{R}+\frac{1}{j{\omega}L}=\frac{1}{R}-j\frac{1}{{\omega}L}{\mathrm{[S]}}\tag{6}

\end{eqnarray}

### Magnitude of the admittance of the RL parallel circuit

We have just obtained the admittance \({\dot{Y}}\) expressed by the following equation.

\begin{eqnarray}

{\dot{Y}}=\frac{1}{R}-j\frac{1}{{\omega}L}{\mathrm{[S]}}\tag{7}

\end{eqnarray}

The magnitude \(Y\) of the admittance of the RL parallel circuit is the absolute value of the admittance \({\dot{Y}}\) in equation (7).

In more detail, the magnitude \(Y\) of the admittance \({\dot{Y}}\) can be obtained by adding the square of the real part \(\displaystyle\frac{1}{R}\) and the square of the imaginary part \(\displaystyle\frac{1}{{\omega}L}\) and taking the square root, which can be expressed in the following equation.

\begin{eqnarray}

Y&=&|{\dot{Y}}|\\

\\

&=&\displaystyle\sqrt{\left(\displaystyle\frac{1}{R}\right)^2+\left(\displaystyle\frac{1}{{\omega}L}\right)^2}\\

\\

&=&\displaystyle\sqrt{\displaystyle\frac{{\omega}^2L^2+R^2}{{\omega}^2L^2R^2}}\\

\\

&=&\displaystyle\frac{\displaystyle\sqrt{R^2+{\omega}^2L^2}}{{\omega}LR}\tag{8}

\end{eqnarray}

From the above, the magnitude \(Y\) of the admittance \({\dot{Y}}\) of the RL parallel circuit becomes the following equation.

Magnitude of the admittance of the RL parallel circuit

\begin{eqnarray}

Y=|{\dot{Y}}|=\displaystyle\sqrt{\left(\displaystyle\frac{1}{R}\right)^2+\left(\displaystyle\frac{1}{{\omega}L}\right)^2}=\displaystyle\frac{\displaystyle\sqrt{R^2+{\omega}^2L^2}}{{\omega}LR}{\mathrm{[S]}}\tag{9}

\end{eqnarray}

Supplement

Some admittance \(Y\) symbols have a ". (dot)" above them and are labeled \({\dot{Y}}\).

\({\dot{Y}}\) with this dot represents a vector.

If it has a dot (e.g. \({\dot{Y}}\)), it represents a vector (complex number), and if it does not have a dot (e.g. \(Y\)), it represents the absolute value (magnitude, length) of the vector.

## Vector diagram of the RL parallel circuit

The vector diagram of the admittance \({\dot{Y}}\) of the RL parallel circuit can be drawn in the following steps.

How to draw a Vector Diagram

- Draw a vector of admittance \({\dot{Y}}_R\) of resistor \(R\)
- Draw a vector of admittance \({\dot{Y}}_L\) of inductor \(L\)
- Combine the vectors

Let's take a look at each step in turn.

### Draw a vector of admittance \({\dot{Y}}_R\) of resistor \(R\)

The admittance \({\dot{Y}}_R\) of resistor \(R\) is expressed by the following equation.

\begin{eqnarray}

{\dot{Y}_R}=\frac{1}{R}\tag{10}

\end{eqnarray}

Therefore, the vector direction of the admittance \({\dot{Y}}_R\) is the direction of the real axis. If the expression does not have an imaginary unit \(j\), the vector does not rotate and is oriented on the real axis. How to determine the vector orientation will be explained in more detail later.

Also, the magnitude (length) \(Y_R\) of the vector of the admittance \({\dot{Y}}_R\) is expressed by the following equation.

\begin{eqnarray}

Y_R=|{\dot{Y}_R}|=\displaystyle\sqrt{\left(\frac{1}{R}\right)^2}=\frac{1}{R}\tag{11}

\end{eqnarray}

### Draw a vector of admittance \({\dot{Y}}_L\) of inductor \(L\)

The admittance \({\dot{Y}}_L\) of inductor \(L\) is expressed by the following equation.

\begin{eqnarray}

{\dot{Y}_L}=-j\frac{1}{{\omega}L}\tag{12}

\end{eqnarray}

Therefore, the orientation of the admittance \({\dot{Y}}_L\) vector is 90° counterclockwise around the real axis. When "\(-j\)" is added to the equation, the vector is rotated 90° clockwise. How to determine the vector orientation will be explained in detail later.

Also, the magnitude (length) \(Y_L\) of the vector of the admittance \({\dot{Y}}_L\) is expressed by the following equation.

\begin{eqnarray}

Y_L=|{\dot{Y}_L}|=\displaystyle\sqrt{\left(\frac{1}{{\omega}L}\right)^2}=\frac{1}{{\omega}L}\tag{13}

\end{eqnarray}

### Combine the vectors

Combining the vector of "admittance \({\dot{Y}}_R\) of resistor \(R\)" and "admittance \({\dot{Y}}_L\) of inductor \(L\)" is the vector diagram of the admittance \({\dot{Y}}\) of the RL parallel circuit.

We have just explained that the admittance \({\dot{Y}}\) of an RL parallel circuit and its magnitude \(Y\) are expressed by the following equation

\begin{eqnarray}

{\dot{Y}}&=&\frac{1}{R}-j\frac{1}{{\omega}L}\tag{14}\\

\\

Y&=&\displaystyle\sqrt{\left(\displaystyle\frac{1}{R}\right)^2+\left(\displaystyle\frac{1}{{\omega}L}\right)^2}\tag{15}

\end{eqnarray}

Supplement

The magnitude (length) \(Y=\displaystyle\sqrt{\left(\displaystyle\frac{1}{R}\right)^2+\left(\displaystyle\frac{1}{{\omega}L}\right)^2}\) of the vector of the synthetic admittance \({\dot{Y}}\) of the RL parallel circuit can also be obtained using the Pythagorean theorem in the vector diagram.

### Vector orientation

Here is a more detailed explanation of how vector orientation is determined.

Vector orientation

When an imaginary unit "\(j\)" is added to the expression, the direction of the vector is rotated by 90°.

- With "\(+j\)" is attached
- The vector rotates 90° counterclockwise.

- With "\(-j\)" is attached
- The vector rotates 90° clockwise.

The admittance \({\dot{Y}_L}\) of the inductor \(L\) is expressed by the following equation

\begin{eqnarray}

{\dot{Y}_L}=-j\frac{1}{{\omega}L}\tag{16}

\end{eqnarray}

Since the expression for the admittance \({\dot{Y}_L}\) of the inductor \(L\) has '\(-j\)', the direction of the vector \({\dot{Y}_L}\) is 90° clockwise rotation around the real axis.

## Admittance phase angle of the RL parallel circuit

The admittance phase angle \({\theta}\) of the RL parallel circuit can be obtained from the vector diagram.

\begin{eqnarray}

{\tan}{\theta}&=&\displaystyle\frac{-\displaystyle\frac{1}{{\omega}L}}{\displaystyle\frac{1}{R}}\\

\\

&=&-\displaystyle\frac{R}{{\omega}L}\\

\\

{\Leftrightarrow}{\theta}&=&{\tan}^{-1}\left(-\displaystyle\frac{R}{{\omega}L}\right)\\

\\

&=&-{\tan}^{-1}\left(\displaystyle\frac{R}{{\omega}L}\right)\tag{17}

\end{eqnarray}

From the above, the admittance phase angle \({\theta}\) of the RL parallel circuit is expressed by the following equation.

Admittance phase angle of the RL parallel circuit

\begin{eqnarray}

{\theta}={\tan}^{-1}\left(-\displaystyle\frac{R}{{\omega}L}\right)\tag{18}

\end{eqnarray}

#### Summary

In this article, the following information on "RL parallel circuit was explained.

- Equation, magnitude, vector diagram, and admittance phase angle of RL parallel circuit admittance

Thank you for reading.

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