[Pulse Wave] RMS Value and Average Value

Regarding the Pulse Wave: This article will explain the information below.

  • How to obtain RMS Value and Average Value

RMS Value and Average Value of Pulse Wave

RMS Value and Average Value of Pulse Wave

The first illustration shows the root mean square (RMS) value and average value of a pulse wave (with a maximum value of \(V_M\) and a period of \(T\)).

Now, let's explain how each of these values are calculated (we strive to include as many intermediate steps as possible).

Waveform of a Pulse Wave

Waveform of a Pulse Wave

To find the root mean square (RMS) value and average value of a pulse wave, we first need to express the pulse wave as a formula.

The pulse wave has different formulas for the red region \(\left(0 \leq t \lt T_1\right)\) and the blue region \(\left(T_1 \leq t \lt T\right)\).

Let's calculate the formulas for the red region and blue region.

Red Region

The region "\(0 \leq t \lt T_1\)" corresponds to the red region.

The red line is always \(V_M\) during the time \(T_1\).

Therefore, the red region can be represented by the following formula.

\begin{eqnarray}
v(t)=V_M
\end{eqnarray}

Blue Region

The region "\(T_2 \leq t \lt T\)" corresponds to the blue region.

The blue rgsion is zero.

Therefore, the blue region can be represented by the following formula.

\begin{eqnarray}
v(t)=0
\end{eqnarray}

By combining the red region and the blue region, the pulse wave can be represented by the following formula.

\begin{eqnarray}
v(t) = \begin{cases}
V_M & \left(0 \leq t \lt T_1\right) \\
\\
0 & \left(T_1 \leq t \lt T\right)
\end{cases}
\end{eqnarray}

RMS Value of a Pulse Wave

The root mean square (RMS) value \(V_{RMS}\) of a waveform \(v(t)\) is the square root of the mean of the square of \(v(t)\). It can be represented by the following formula:

\begin{eqnarray}
V_{RMS} &=& \sqrt{\displaystyle\frac{1}{T} \displaystyle \int_{0}^{T}v(t)^2dt}
\end{eqnarray}

The red region is \(0 \leq t \lt T_1\)", and the blue region is "\(T_1 \leq t \lt T\)".

In the formula for finding the absolute value, if we separate the red region and the blue region, we get the following formula.

\begin{eqnarray}
V_{RMS} &=& \sqrt{\displaystyle\frac{1}{T} \left(\displaystyle \int_{0}^{T_1}v(t)^2dt+\displaystyle \int_{T_1}^{T}v(t)^2dt\right )}\\
\\
&=& \sqrt{\displaystyle\frac{1}{T} \left(\displaystyle \int_{0}^{T_1}V_M^2dt+\displaystyle \int_{T_1}^{T}0\right )}\\
\\
&=& \sqrt{\displaystyle\frac{1}{T} \displaystyle \int_{0}^{T_1}V_M^2dt}
\end{eqnarray}

\(V_M^2\) is not a variable that changes with time \(t\), but a constant. Therefore, it can be taken out of the integration. As a result, the following equation is obtained.

\begin{eqnarray}
V_{RMS} &=& \sqrt{\displaystyle\frac{1}{T_1} V_M^2\displaystyle \int_{0}^{T}1dt}\\
\\
&=& V_M\sqrt{\displaystyle\frac{1}{T_1} \displaystyle \int_{0}^{T}1dt}
\end{eqnarray}

When calculating the above equation, the following formula is obtained.

\begin{eqnarray}
V_{RMS} &=& V_M\sqrt{\displaystyle\frac{1}{T} \left[t\right]_{0}^{T_1}}\\
\\
&=& V_M\sqrt{\displaystyle\frac{1}{T} \left(T_1-0\right)}\\
\\
&=& \sqrt{\displaystyle\frac{T_1}{T}}V_M
\end{eqnarray}

Therefore, the root mean square (RMS) value \(V_{RMS}\) of the pulse wave is as follows.

\begin{eqnarray}
V_{RMS} =\sqrt{\displaystyle\frac{T_1}{T}}V_M
\end{eqnarray}

Average Value of a Pulse Wave

The average value \(V_{AVE}\) of a waveform \(v(t)\) is the average value of the absolute value \(|v(t)|\) of \(v(t)\) and can be represented by the following formula:

Formula to find the average value

\begin{eqnarray}
V_{AVE} &=& \displaystyle\frac{1}{T} \displaystyle \int_{0}^{T}|v(t)|dt
\end{eqnarray}

This formula for calculating the average value uses the absolute value \(|v(t)|\) of \(v(t)\).

Therefore, if there is a negative region in the waveform, it needs to be converted so that the negative region becomes positive.

In the case of a pulse wave, there is no negative region, so the formula for \(v(t)\) and the formula for the absolute value \(|v(t)|\) of \(v(t)\) become the same.

Therefore, the absolute value \(|v(t)|\) of \(v(t)\) can be represented by the following formula.

\begin{eqnarray}
|v(t)| = \begin{cases}
V_M & \left(0 \leq t \lt T_1\right) \\
\\
0 & \left(T_1 \leq t \lt T\right)
\end{cases}
\end{eqnarray}

In the formula to find the average value, if we separate each term, we get the following formula.

\begin{eqnarray}
V_{AVE} &=& \displaystyle\frac{1}{T} \displaystyle \int_{0}^{T}|v(t)|dt\\
\\
&=& \displaystyle\frac{1}{T} \left(\displaystyle \int_{0}^{T_1}|v(t)|dt+\displaystyle \int_{T_1}^{T}|v(t)|dt\right )\\
\end{eqnarray}

Since the pulse wave is zero in the region \(T_1 \leq t \lt T\), the above equation becomes:

\begin{eqnarray}
V_{AVE} &=& \displaystyle\frac{1}{T} \left(\displaystyle \int_{0}^{T_1}|v(t)|dt+\displaystyle \int_{T_1}^{T}0dt\right )\\
\\
&=&\displaystyle\frac{1}{T} \displaystyle \int_{0}^{T_1}|v(t)|dt\\
\end{eqnarray}

In the above equation, when substituting \(v(t)=V_M\), the following formula is obtained.

\begin{eqnarray}
V_{AVE} &=& \displaystyle\frac{1}{T} \displaystyle \int_{0}^{T_1}V_Mdt\\
\\
&=& \displaystyle\frac{1}{T} V_M\displaystyle \int_{0}^{T_1}1dt\\
\\
&=& \displaystyle\frac{1}{T}V_M \left[t\right]_{0}^{T_1}\\
\\
&=& \displaystyle\frac{1}{T}V_M \left(T_1-0\right)\\
\\
&=&\displaystyle\frac{T_1}{T}V_M
\end{eqnarray}

Therefore, the average value \(V_{AVE}\) of the pulse wave is as follows.

\begin{eqnarray}
V_{AVE} &=& \displaystyle\frac{T_1}{T}V_M
\end{eqnarray}

Summary

In this article, the following information on the "Pulse Wave" was explained.

  • How to obtain RMS Value and Average Value

Thank you for reading.